13x^2-3x=190

Solution for 13x^2-3x=190 equation:

13x^2-3x=190

We move all terms to the left:

13x^2-3x-(190)=0

a = 13; b = -3; c = -190;
Δ = b2-4ac
Δ = -32-4·13·(-190)
Δ = 9889
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{9889}}{2*13}=\frac{3-\sqrt{9889}}{26}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{9889}}{2*13}=\frac{3+\sqrt{9889}}{26}
$